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A.2 · Quiz · A.2 Forces and momentum · practice

Quiz: momentum and force

Ten multiple-choice questions on Newton’s second and third laws and on momentum.

SL+HLMedium20 minFree
Hook

Ten questions. A wrong answer links back to the lesson that covers it, and you can try again as often as you like.

Check 1 of 10

A trolley moves along a level track. A constant forward force F and a constant backward drag of 5.0 N act on it, and no other horizontal forces. Its momentum falls from 4.5 kg m s⁻¹ to 2.1 kg m s⁻¹ in 0.60 s. What is F?

Check 2 of 10

A quadcopter of mass 0.80 kg hovers at a fixed point. Each of its four rotors pushes 0.25 kg of air vertically downwards every second. Take g = 9.81 m s⁻² and assume the air above is at rest. What is the speed of the air leaving each rotor?

Check 3 of 10

The net external force on a trolley that starts from rest is slowly increased. Which describes the trolley’s momentum–time graph?

Check 4 of 10

A hose delivers 180 kg of water per minute. The water leaves horizontally at 8.0 m s⁻¹. What is the minimum force needed to hold the hose still?

Check 5 of 10

A 2.0 kg trolley moves forward at 9.0 m s⁻¹. A constant resultant force of 6.0 N acts backwards on it for 2.0 s. What is its velocity afterwards?

Check 6 of 10

Two isolated trolleys, 3.0 kg and 1.5 kg, are pushed apart by a spring between them. During the push the 3.0 kg trolley has an average acceleration of 2.0 m s⁻². What is the average acceleration of the 1.5 kg trolley?

Check 7 of 10

A 150 g tennis ball hits a wall at 24 m s⁻¹ and rebounds along the same line at 12 m s⁻¹. It is in contact with the wall for 0.030 s. What is the average force of the wall on the ball?

Check 8 of 10

Which statement is the most general form of Newton’s second law?

Check 9 of 10

A 250 g puck slides at 8.0 m s⁻¹ towards a rink board, rebounds at 3.0 m s⁻¹ in the opposite direction, and is in contact with the board for 0.20 s. What is the average force of the board on the puck?

Check 10 of 10

A constant resultant force F acts on an object of mass m for a time t, starting from rest. What is the object’s change in velocity?

Summary card

Key points

  • • F_net = Δp / t; the gradient of a p–t graph is the net force.
  • • Rate of change of momentum: (mass per second) × (velocity change).
  • • A rebound reverses the direction: subtract velocities with signs.

Formulas

  • F = Δp / t
  • Ft = Δp
  • Δp = m(vf − vi)

Key terms

Impulse
:
Ft, equal to the change in momentum

Common errors

  • • Subtracting speeds after a rebound.
  • • Forgetting to convert grams to kilograms or minutes to seconds.
Checks solved: 0 of 10