CritABCD
A.1 · 7 · A.1 Kinematics · motion graphs, uniform and non-uniform motion

Motion graphs: x–t, v–t, a–t

Three linked graphs describe the same motion. Read the slope, read the area, and tell uniform from non-uniform.

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Hook

One motion, three graphs: where it is, how fast it is going, how quickly that speed is changing. Each graph hides the other two inside its slope and its area.

Why graph?
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A graph is a picture of data

A graph is a visual representation of data: each point pairs two physical quantities. The equation y = mx is a straight line through the origin. This kind of relationship is called direct proportionality: if one quantity doubles, the other doubles too.

Check 1 of 5

On a position–time graph, a steeper straight line means…

Check 2 of 5

The area under a velocity–time graph gives…

Check 3 of 5

A flat, horizontal line on a v–t graph means…

Check 4 of 5

The v–t graph of an object rises steadily from 5 m s⁻¹ to 25 m s⁻¹ in 4 s. Its acceleration, the gradient, is…

Check 5 of 5

The area under an a–t graph gives…

Apply

A cyclist starts at 2 m s⁻¹ and speeds up uniformly to 8 m s⁻¹ in 6 s. Sketch the v–t graph in words, find the acceleration from its gradient, and find the distance from its area.

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Remember earlier lessons
From lesson A.1 · 6

Displacement is…

From lesson A.1 · 4

For uniform motion, Y = …

Summary card

Key points

  • • x–t slope = velocity; v–t slope = acceleration; v–t area = displacement; a–t area = change in velocity.
  • • Uniform motion: x–t is a straight line, v–t is flat, a = 0.
  • • Non-uniform motion: x–t curves; the tangent at a point gives the instantaneous velocity; x = ut + ½at².

Formulas

  • v = Δx / t
  • x_f = x_i + ut + ½at²
  • area under v–t = displacement

Key terms

Gradient
:
rise / run, the slope of a graph
Tangent
:
a straight line touching a curve at one point; its slope is the instantaneous gradient

Common errors

  • • Reading the height of a v–t graph as the distance instead of the AREA.
  • • Confusing "flat v–t line" with "at rest".
  • • Measuring a gradient with a chord instead of a tangent.
Checks solved: 0 of 5